Question

please solve the question step by step in a copy with solution.

Answer 1

let the total distance be A,

then

total distance travelled by the man by train, bus and car = 2A/5 + A/3 + A/4,

=(24A+20A+15A)/60,

=59A/60,

then

remaining distance=total distance - travelled distance,

= A - 59A/60,

=(60A-59A)/60,

=A/60,

but account to the question, reamaining distance is 3 km,

then

A/60 = 3 km,

therefore

A=3×60,

A=180 km,

hence

distance travelled by train

= 2A/5,

=2 × 180/5,

=2×36,

=72 km,




IInd approach:-



Distance travelled by train + distance travelled by bus + distance travelled by car + distance travelled by foot = total distance travelled,

hence

2A/5 + A/3 + A/4 + 3 = A,

(24A+20A+15A+180)/60 = A,

59A + 180 = 60×A,

59A+180=60A,

then

180=60A-59A,

180=A,

then

distance travelled by train = 2A/5,

=2×180/5,

=2×36,

=72 km