Please solve the question *USING ONLY 1 VARIABLE*
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Answered by
4
Hi ,
Let x , ( 64 - x ) are two parts ,
here ,
bigger part = x ,
smaller part = ( 64 - x )
according to the problem given ,
3x = 5( 64 - x )
3x = 320 - 5x
3x + 5x = 320
8x = 320/8
x = 40
Therefore ,
buggy part = x = 40
smaller part = 64 - 40 = 24
I hope this helps you.
: )
Let x , ( 64 - x ) are two parts ,
here ,
bigger part = x ,
smaller part = ( 64 - x )
according to the problem given ,
3x = 5( 64 - x )
3x = 320 - 5x
3x + 5x = 320
8x = 320/8
x = 40
Therefore ,
buggy part = x = 40
smaller part = 64 - 40 = 24
I hope this helps you.
: )
Answered by
0
。☆✼★━━━━━━━━━━━━━━━★✼☆。
Larger part is 40 and smaller part is 24
。☆✼★━━━━━━━━━━━━━━━★✼☆。
Larger part is 40 and smaller part is 24
。☆✼★━━━━━━━━━━━━━━━★✼☆。
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