Question

Please Solve the question with steps .​

Answer 1

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Step-by-step explanation:

Given:

S10=99+T1..........(i)S10=89+T6..........(ii)

where S10 is the sum of 10 terms of the A.P. and T1,T6 are the first and sixth term respectively.

Say a and d are the first term and common difference of the A.P. respectively.

∴S10=5{2a+9d};T1=a;T6=a+5d........(iii)∴5{2a+9d}=a+99........(iv)5{2a+9d}=a+89+5d........(v)

Subtracting (iv) and (v), we get,

10−5d=0=>d=2........(vi)

Also given that

T1+T5=10=>a+a+4d=10=>2a+4×2=10=>2a=2=>a=1

∴T3=a