please solve the questions 14 and 15
Answers
Sol 14. Let the length nd breadth of the rectangular garden be x nd y respectively.
ATQ ,
x = y + 4 ....... (i)
=> Half perimeter of rectangular garden = 36
=> x + y = 36
=> y + 4 + y = 36 ( from i )
=> 2y = 32
=> y = 16 m
Putting value of y in eqⁿ i
x = y + 4
= 16 + 4
= 20 m
Hence the length nd breadth of the rectangular garden are 20 m nd 16 m respectively.
Sol 15. Let P ( 2,-3 ) nd Q ( 10,y ) be ( x1,y1 ) nd ( x2,y2 ) respectively.
Distance formula = √ ( x1 - x2 )² + ( y1 - y2 )²
ATQ,
PQ = 10
=> (PQ)² = (10)² ( squaring both sides )
=> { √ ( x1 - x2 )² + ( y1 - y2 )² }² = 100
=> ( x1 - x2 )² + ( y1 - y2 )² = 100
=> ( 2 - 10 )² + ( -3 - y )² = 100
=> (-8)² + ( 9 + y² + 6y ) = 100
=> 64 + 9 + y² + 6y = 100
=> y² + 6y + 73 - 100 = 0
=> y² + 6y - 27 = 0
=> y² + 9y - 3y - 27 = 0
=> y ( y + 9 ) - 3 ( y + 9 ) = 0
=> ( y + 9 ) ( y - 3 ) = 0
y = 3 nd y = -9
=> distance can never be in negative.
Therefore, y = 3.
#_answer_with_quality......
mark me brainliest if it's helpful to uhh.....!!!!