Question

Please Solve the questions and explain it why ? For tennetiraj SIR


OTHER USERS EXCEPT TENNETIRAJ SIR WILL BE REPORTED. ​

Answer 1

Answer:

Q1 : a

Q2: d

Q3: C

Step-by-step explanation:

Answer 2

Answer:

1.a

2.d

3.c

4.b

5.a

6.c

Step-by-step explanation:

1. The diagonals of a rhombus bisect to each other .

2.Given that

PQRS is a square and PQ = (2x+3) cm

and QR = (3x-5) cm

We know that

All sides are equal in a square .

=> PQ = QR = RS = PS

=> 2x+3 = 3x-5

=> 3+5 = 3x-2x

=> 8 = x

=> x = 8

Therefore, The value of x = 8 cm

3.Given that

√11025 = 105

Now,

√1.1025

=> √(11025/10000)

=> √(105²/100²)

=> √(105/100)²

=> 105/100

=> 1.05

Therefore, √1.1025 = 1.05

4.Let the digit at tens place of a two digits number be X

The place value of X = 10×X = 10X

The units digit = 5 more than its tens digit

= X+5

The place value of units digit

= (X+5)×1

= X+5

Now

The two digits number

= 10X+X+5

=> 11X+5

Therefore ,The two digits number = 11X+5

5.Given number = | -4/5 |

=> 4/5

Multiplicative inverse of 4/5 = 5/4

6.Given classes are 0-15, 15-30 ,...

Class size = 15

Therefore, The next classes will be

30-45,45-60,60-75,75-90,...

The fourth class = 45-60

The upper limit = 60