PLEASE SOLVE THE QUESTIONS NUMBER 20 OF THE ATTACHED IMAGE...........
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hey here is your answer .
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GIVEN : The perimeter of a triangular field = 540m
Let the sides are 25x , 17x , 12 x
Perimeter of a ∆ = sum of three sides
25x + 17x + 12x = 540
54x = 540
x = 10
1st side (a) - 25x = 25×10= 250m
2nd side(b)= 17x = 17×10= 170m
3rd side (c)= 12x = 12 × 10 =120m
Semi - perimeter ( S) = a+b+c/2
= (250 + 170+120)/2 = 540/2 = 270 m
Area of the ∆= √ S(S - a)(S - b)(S - c)
[By Heron’s Formula]
= √ S(S - 250)(S - 170)(S - 120)
= √ 270(270 - 250)(270 - 170)(270 - 120)
= √ 270× 20×100×150
= √ 81000000
Area of the ∆= 9000 m²
Hence, the Area of the ∆= 9000 m²
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