Math, asked by praveeshprakash2020, 6 hours ago

Please solve the riddle which I have attached below

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Answers

Answered by tennetiraj86
4

Step-by-step explanation:

Solution :-

Picture -1:-

Let the value of Take 1 clap board be X

The value of Take 2 clap board = 2X

The value of Take 3 clap board = 3X

The value of Take 5 clap board = 5X

Given that

Sum of the Take 2, Take 3 and Take 5 clap boards = 50

=> 2X+3X+5X = 50

=> 10X = 50

=> X = 50/10

=> X = 5

The value of Take 1 clap board = 5

Picture -2:-

Let the value of a camera be Y

Sum of three cameras = 30

=> Y+Y+Y = 30

=> 3Y = 30

=> Y = 30/3

=> Y = 10

The value of a camera = 10

Picture -3:-

Let the value of One Wheel be Z

Sum of two wheels and take 4 clap board =30

=> Z+Z + (4×5) = 30

=> 2Z +20 = 30

=> 2Z = 30-20

=> 2Z = 10

=> Z = 10/2

=> Z = 5

The value of a wheel = 5

Picture -4:-

take 1 board + Take 9 board × Camera with wheels

=> (1×5)+(9×5)×(10+2×5)

=> 5+45×(10+10)

=> 5+45×20

=> 5+900

=> 905

Answer:-

The answer for the given problem is 905

Answered by samerru
0

Answer:1000

Step-by-step explanation:

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