Question

please solve the seventh question I will mark you brainliest

Answer 1

Pls, MARK AS BRAINLIEST.

Let the distance of the office be x Km

Time taken at 20 km/hr is x/20 hr; reaches 20/60=1/3hr=20mt late

Time taken at 30 km/hr is x/30 hr; reaches 15/60=1/4hr=15mt early

Therefore, x/20 − x/30= 1/3 + 1/4

or

x/60 =7/12

or

x

=

7/12.60 = 35 Km

Time taken at 30 km/hr is 35/30=35/30⋅60 = 70 mt

Time taken at 25 km/hr is 35/25=7/5 hr = 7/5⋅60 = 84mt;

So travelling at 25 km/hr, she will reach 70+15−84=1 mt early