Question

Please solve the sum

Answer 1

Answer: d) 1/√3 and -1/√3

Step-by-step explanation:

To find zeroes p(x) will be equal to 0.

So 3x^2-1=0

3x^2=1

x^2=1/3

x=±√(1/3)

x=±1/√3

Answer 2

Option (d) ✔

Solution :

Given that :

Polynomial

$p(x) = 3 {x}^{2} - 1 \\ \\ = > p(x) = 0 \\ \\ = > 3 {x}^{2} - 1 = 0 \\ \\ = > {x}^{2} = \frac{1}{3} \\ \\ = > x = \binom{ + }{ - } \sqrt{ \frac{1}{3} } \\ \\ = > x = \binom{ + }{ - } \frac{1}{ \sqrt{3} }$

So, the zeroes of the polynomial will be 1/√3 and -1/√3 ✔

I hope it will be helpful for you ☺