Question

PLEASE SOLVE THE SUM .
DON'T SPAM.​

Answer 1

Step-by-step explanation:

Given :-

log 4 ^log2^log√2^log3^(x-2006) =0

To find:-

Find the value of x for :

log 4 ^log2^log√2^log3^(x-2006) = 0

Solution:-

Given that:

log 4 ^log2^log√2^log3^(x-2006) =0

We know that

a^x= N=> log a(N) = x

=> log2^log√2^log3^(x-2006) = 4^0

=> log2^log√2^log3^(x-2006) = 1

Again On applying above formula

=> log√2^log3^(x-2006) = 2^1

=> log√2^log3^(x-2006) = 2

Again On applying above formula

=> log3^(x-2006) = (√2)^2

=> log3^(x-2006) = 2

Again On applying above formula

=> x-2006 = 3^2

=> x-2006 = 9

=> x = 9+2006

=>x = 2015

Answer:-

The value of x for the given problem is 2015

Used formula:-

• a^x= N=> log a(N) = x
• Where base is a ,number is N
• ^ represents power

Answer 2

Step-by-step explanation:

x = 2015

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