please solve the sum no. 3. roman no. 8 by using only column method and mention the reasons that why you are putting the algebraic signs.
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Answer :
3. (viii)
The terms are
9abc, - 6bc, abc, - bc
Short method :
9abc + ( - 6bc) + abc + ( - bc)
= (9abc + abc) + {(- 6bc) + (- bc)}
= (9 + 1) abc + (- 6 - 1) bc
= 10 abc - 7 bc
Column method :
We write the terms as the sum of two terms in order to add them as follows -
(9abc - 6bc) and (abc - bc)
So,
9abc - 6bc
+ abc - bc
__________
10abc - 7bc
Note :
( - ) + ( - ) = ( - )
#MarkAsBrainliest
3. (viii)
The terms are
9abc, - 6bc, abc, - bc
Short method :
9abc + ( - 6bc) + abc + ( - bc)
= (9abc + abc) + {(- 6bc) + (- bc)}
= (9 + 1) abc + (- 6 - 1) bc
= 10 abc - 7 bc
Column method :
We write the terms as the sum of two terms in order to add them as follows -
(9abc - 6bc) and (abc - bc)
So,
9abc - 6bc
+ abc - bc
__________
10abc - 7bc
Note :
( - ) + ( - ) = ( - )
#MarkAsBrainliest
anushka7337:
yes
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