please solve them correctly
Answers
Answer:
i am sorry i only know this much so i thought i would help you with this.
5 i ]1÷18
5 ii]1÷12
5 iii]1÷9
6]3÷8
Step-by-step explanation:
answer 5i]probability of getting 3 as sum of two dices when thrown=[2+1]
=[1+2]
total outcomes=36
No. of favorable outcomes=2
therefore,probability= No. of favorable outcomes÷total number of outcomes
=2÷36
=1÷18
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answer 5 ii]probability of getting 4 as sum of two dices when thrown=[2+2],[3+1],[1+3]
total outcomes=36
No. of favorable outcomes=3
therefore,probability= No. of favorable outcomes÷total number of outcomes
=3÷36
=1÷12
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answer 5 iii]probability of getting 5 as sum of two dices when thrown=[1=4],{4=1],[2+3],[3+2]
total outcomes=36
No. of favorable outcomes=4
therefore,probability= No. of favorable outcomes÷total number of outcomes
=4÷36
=1÷9
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answer 6]probability of getting exactly 2 tails when 2 coins are tossed=3,[TTH],[THT],[HTT]
total outcomes=8
No. of favorable outcomes=3
therefore,probability= No. of favorable outcomes÷total number of outcomes
=3÷8
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