Question

Please solve these ??​

Answer 1

Given : 9 Empty boxes ( 3  * 3) & their multiplication output   across row & columns

To find : Fill the boxes with 1 to 9 Digits without any repetition so that all rows & column satisfied

Solution:

5 & 7 are prime numbers whose multiples are not available from 1 to 9

Let see which numbers should have these factors

21  & 56 should have  7 as Factor

Hence 3rd row last column   must be 7  as that is common factor of both

120 * 180 should have 5 as Factor

Hence 2nd row 2nd column must have 5 as that is common factor of both

21  =  7  * 1  * 3   ( only possible)

but if we use 1 in 2nd row , 3rd column then

24 * 1 * 5 = 120   ( not possible)

Hence

3 will be in 2nd row , 3rd column   & 1 will be in 1st row , 3rd column

2nd row 1st column = 120 / (3 * 5) = 8

Solving this way we can reach that

6   X    9   X     1      =  54

X          X          X        

8    X    5    X   3    = 120

X           X         X

2    X     4    X   7     = 56

=             =         =

96         180       21

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