Question

please solve these 2 except 1​

Answer 1

Step-by-step explanation:

2) p(x) = x² - x - 6 = 0

          = x² - (3-2)x -6 = 0

          = x² - 3x - 2x - 6 = 0

          = x(x - 3) -2(x - 3) = 0

          = (x-2)(x-3) = 0

x -2 = 0           OR        x-3 = 0

x = 0+2           OR        x = o+3

x = 2               OR        x =3

THEREFORE, ZEROES OF THE POLYNOMIAL ARE 2 AND 3

3) p(x) = (x+2)(x-1) = 0

  x + 2 = 0        OR        x - 1 = 0

  x = 0 - 2         OR        x = 0 + 1

  x = -2             OR        x = 1

THEREFORE , ZEROES OF THE POLYNOMIAL ARE (-2) AND 1

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