Question

please solve these 2 questions class 12th maths derivatives ​

Answer 1

Answer:

$\red { \frac{dy}{dx}}\green {=\frac{1}{\sqrt{x}}}$

Step-by-step explanation:

$\red { y = sin^{-1}\big( \frac{2tan \sqrt{x}}{1+tan^{2} \sqrt{x}}\big)}$

$\implies y = sin^{-1}\left( sin\: 2 \sqrt{x}\right)$

$\boxed {\pink { \frac{2tanA}{1+tan^{2}A}= sin2A}}$

$\implies \frac{dy}{dx} = 2\times \frac{1}{2\sqrt{x}}$

$= \frac{1}{\sqrt{x}}$

Therefore.,

$\red { \frac{dy}{dx}}\green {=\frac{1}{\sqrt{x}}}$

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Answer 2

Answer:

Step-by-step explanation: