Question

please solve these 4 question​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Q1

$2( \frac {1}{0} \: \: \frac{3}{x} ) + ( \frac{y}{1} \: \: \frac{0}{2} ) > ( \frac{5}{1} \: \: \: \frac{6}{8} ) \\ (\frac{2}{0} \: \: \frac{6}{2x}) + (\frac{y}{1} \: \: \frac{0}{2}) > (\frac{5}{1} \: \: \frac{6}{8} ) \\ ( \frac{2 + y}{1} \: \: \frac{6}{2x + 2} ) \: \: \ > (\frac{5}{1} \: \: \frac{6}{8}) \\ 2 + y = 5 \: \: \: \: \: \: \: \: \: \: \: 2x + 2 = 8 \\ y = 5 - 2 \: \: \: \: \: \: \: \: \: \: \: 2x = 8 - 2 \\ | y = 3 | \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: | x = 3 |$

Q2

$\: \: \: \: \: \: \: \: a = ( \frac{1}{4} \: \: \frac{2}{2}) \: \: \: \: \: \\ \: \: \: \: \: \: \: \: 2a = ( \frac{2}{8} \: \: \frac{4}{4} ) \: \: \: \: \: \: \: \\ |2a | = \frac{2}{8} \frac{4}{4} \: \: \: \: \: \: \: \: \\ |2a| = 8 - 32 \\ |2a| = - 24 \: \: \: \: \:$

Q3

$\sec {}^{2} {60}^{0} - tan {}^{2} 60 {}^{0 } \\ \: \: \: \: ({2})^{2} - (\sqrt{3} ) {}^{2} \\ 4 - 3 \\ \: \: \: 1 \: \:$

Q4

$\binom{\cos \: q \: \: \: \: - \sin \: \: \: \: q}{\sin \: q \: \: \: \: - \cos \: q} \\ = \cos {}^{2} q + \sin {}^{2} q \\ = 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Step-by-step explanation:

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