Question

please solve these all questions . Correct answer will be mark as brainlist +20 thanks​

Answer 1

$1.Given \: sides \: = \: 12 \: and \: 35 \\ </p><p>By \: pythagoras \: theorem, \: \\ </p><p> {hypotnuse}^{2} = {12}^{2} + {35}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \ = 144 \: + 1225 \\ \: \: \: \: = 1369 \\ = \sqrt{1369} \\{hypo. }^{2} = 37</p><p>$

Answer 2

Answer:

Area = 140cm²

Let, the length and breadth be 4x and 6x

ATP

\begin{gathered}4x \times 6x = 140 \\ = ) \: 24 {x}^{2} = 140 \\ = ) \: {x}^{2} = \frac{140}{24} \\ = ) \: {x}^{2} = 5.83 \\ = ) \: x = \sqrt{5.83} = 2.415\end{gathered}

4x×6x=140

=)24x

2

=140

=)x

2

=

24

140

=)x

2

=5.83

=)x=

5.83

=2.415

Ans:- Length = (4×2.415)m = 9.66m

Breadth = (6×2.415)m = 14.49m