Question

please solve these for me...​

Answer 1

Answer:

1. 43

2. 110.

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Answer 2

Answer:

I) the sum of angles of triangles is equal to 180°

so, 50°+82°+x=180°

132°+x=180°

x=180°-132°

x=48°

II) let us consider it as ∆ABC

A+B+C=180°(angle-sum property of ∆)

65°+45°+C=180°

110°+C=180°

C=180°-110°

C=70°

C+X=180°(linear pair)

70°+X=180°

X=180°+70°

X=110°