Question

please solve these problems​

Answer 1

$1- p(1)=5×1^2−3×1+7$

=12−3

=9

2-in image

3-in image

4-i-Here, p(x)=3x−2.

In order to find zero of p(x), we equate p(x) to 0,

i.e p(x)=0.

⇒3x−2=0⇒3x=2⇒x=$\frac{2}{3}$

∴ $\frac{2}{3}$ is the zero of p(x).