please solve these question
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which one there are many. or all questions?
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Here as given in quention
b is 3 times of A
therefore
b=3a.
now
c get half of b
therefore
c=b/2
=3a/2
A +B+ C=715
A+3A+3A/2=715. ( substituting b=3A and. c=
3a/2)
11A/2=715
11A = 1430
A = 130
Substituting A =130
B=3a
B=3*130
B=390
C= 3A/2
C=150*3/2
C=195
hence
A= 150, B=390, C=195
b is 3 times of A
therefore
b=3a.
now
c get half of b
therefore
c=b/2
=3a/2
A +B+ C=715
A+3A+3A/2=715. ( substituting b=3A and. c=
3a/2)
11A/2=715
11A = 1430
A = 130
Substituting A =130
B=3a
B=3*130
B=390
C= 3A/2
C=150*3/2
C=195
hence
A= 150, B=390, C=195
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