Physics, asked by Anonymous, 9 months ago

please solve these questions.

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Answered by BRAINLYADDICTOR

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Answer:

42)(c)2r

➡️Because displacement is twice the radius(r) = 2×r=>2r

43)(d) equal to 1 or less than 1

44)a boy is sitting on a merry-go-round which is in motion. So the boy is in accelerated motion.

➡️(c) in accelerated motion.

45)magnitude of the displacement and distance moved are same so the car is moving on straight road.

➡️a) if the car is moving on straight road.

46)0.06m/s

➡️We have to convert m/s in km/hr

➡️0.06=0.06×3600/1000

➡️0.06×36/10

➡️6/1000×36

➡️216/1000

➡️0.216km/hr

C) 0.216km/hr $follow and thank my answers.$

Answered by Anonymous

Answer :

(42). b[πr] because the circumference of the circle = 2πr

and, the displacement after the half circle will be covered = 2πr/2 = πr

$\rule{100}{2}$

(43). (d) equal to 1 or less than 1

$\rule{100}{2}$

44)a boy is sitting on a merry-go-round which is in motion. So the boy is in accelerated motion.

∴ Option C is correct (in accelerated motion.)

$\rule{100}{2}$

(45). magnitude of the displacement and distance moved are same so the car is moving on straight road.

∴ Option A is correct ( if the car is moving on straight road.)

$\rule{100}{2}$

(46). We have to convert 0.06 m/s into km/h

Multiply by 18/5

⇒ 0.06 × 18/5

⇒ 0.216 km/hr

C) 0.216 km/hr

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