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24.Given that,u=5m/s
a=0.2m/s², t=10
From the first law of motion,
V=u+at
V=5+0.2×10=7m/s
Now from the second law of motion,
S=ut+1/2at²
S=50+10=60m
25.Given that u=18km/hr=18×5/18m/s
u=5m/s, v=0
t=2.5seconds
From the first law of motion,
V=u+at
5+2.5a=0
2.5a=-5
a=-2
Negative symbol concludes that it is a retardation.......
26.Given that,
u=0, a=0.2m/s², t=5 second
From the first law of the motion,
V=u+at
V=5×0.2=1m/s
From the second law of the motion,
S=ut+1/2at²
S=0.1×25=25/10=2.5m
Distance travelled=2.5m
Explanation:
Hope it helps you frnd.......
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Hope it helps mate.
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