Please solve these questions....
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Please solve these questions....
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(a)
Angle AOC =47°
AOC+COB=180° (Lenior pair)
47+COB=180
COB=180-47
COB=133°
AOC=DOB ( Vertical opposite angle)
DOB=47°
AOD=COB (Vertical opposite angle)
AOD=133°
(b)
SOQ=POR (Vertical opposite angle)
POR=105°
SOQ+SOP=180 (Lenior pair)
105+SOP=180
SOP=75°
SOP=QOR
QOR=75°
MR.SKETCH✌️
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Answer:
(a)<AOC +<BOC = 180° (linear pair)
=> 47° + <BOC = 180°
=> <BOC = 133°
Now ,
<BOC = <AOD = 133° (vertically opposite angle)
=> <AOD = 133°
also, <AOC = <BOD (vertically opposite angle)
=> <BOD = 47°
(b) <SOQ +<QOR = 180°(linear pair)
=> <QOR + 105° = 180°
=> <QOR = 75°
Now,
<SOQ = <POR (vertically opposite angle)
<POR = 105°
also,
<ROQ = <POS (vertically opposite angle)
<ROQ = 75°
hope it helps :-))
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