Question

please solve these questions​

Answer 1

Answer:

2. Debroglie wavelength, lambda =

$h \div \sqrt{2m \times k.e}$

where h is plank's constant

m is mass and k.e is kinetic energy

By, putting values in equation

Ratio of lambda of electron: Proton : alpha particle = 1/4 : 1/42.8×2 : 1/1.41×42.8

Note - Ratio of mass of proton to electron is 1836 and proton to alpha particle 2

1. Debroglie wavelength formula by equating temperature, lambda =

$h \div \sqrt{3mkt}$

where, k is a constant

h is plank's constant

m is mass and t is temperature

Debroglie wavelength ratio helium to neon is =

$1 \div \sqrt{4 \times 200} \div 1 \div \sqrt{20 \times 1000}$

= 26.5

hope this will help you