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6) ACB = 180-130= 50
ABC + BAC + ACB= 180
BAC + 80 + 50 = 180
BAC= 50
7)BAP+ APB+ ABP= 180
60 + 90 + BAP= 180
BAP = 30
AS IT IS ISOSCELES
SO ABC = ACB = 60
8)110 = 40 +Y( EXTERIOR ANGLE IS EQUAL TO SUM OF 2 OPPOSITE INTERIOR ANGLE)
Y = 70
110+X = 180
x= 70
AS X= Y = 70
SO IT IS ISOSCELES
ABC + BAC + ACB= 180
BAC + 80 + 50 = 180
BAC= 50
7)BAP+ APB+ ABP= 180
60 + 90 + BAP= 180
BAP = 30
AS IT IS ISOSCELES
SO ABC = ACB = 60
8)110 = 40 +Y( EXTERIOR ANGLE IS EQUAL TO SUM OF 2 OPPOSITE INTERIOR ANGLE)
Y = 70
110+X = 180
x= 70
AS X= Y = 70
SO IT IS ISOSCELES
RajniJamwal:
Thanks
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