please solve these questions.....
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A) step 1:- angle BAC+angleA=180
angleBAC+70=180
angleBAC=180-70
angleBAC=110
Srep 2:- as side AB and AC are same then ,
angleABC and angleACB [opposite
angles of the equal sides will be
same]
let's take angleABC and angleACB as
'x'
Therefore, angle ABC+angleACB =2x
Step 3:- angle ABC + angle ACB +angle BAC
=180
2x + 110 =180
2x=180-110
x=70÷2=35
ABC=35 , ACB=35 , BAC=110
B) step 1:-angle QPR=65 (vertically opposite angles)
step 2:- angle QPR = angle QRP
Step 3:- angle QPR +angle QRP +angle PQR = 180
65+65+angle PQR=180
130+angle PQR =180
angle PQR =180-130=50
QPR=65 , QRP=65 , PQR=50
C) step 1:- angle CAM + angle MAN=180
angle 135 + angle MAN =180
angle MAN =180-135=45
Step 2:-angle MAN = angle MNA [Same side]
Step 3:- angle MAN + angle MNA + angle AMN = 180
35+35+angle AMN =180
angle AMN =180-70=110
MAN = 35 , AMN = 110 , MNA = 35
angleBAC+70=180
angleBAC=180-70
angleBAC=110
Srep 2:- as side AB and AC are same then ,
angleABC and angleACB [opposite
angles of the equal sides will be
same]
let's take angleABC and angleACB as
'x'
Therefore, angle ABC+angleACB =2x
Step 3:- angle ABC + angle ACB +angle BAC
=180
2x + 110 =180
2x=180-110
x=70÷2=35
ABC=35 , ACB=35 , BAC=110
B) step 1:-angle QPR=65 (vertically opposite angles)
step 2:- angle QPR = angle QRP
Step 3:- angle QPR +angle QRP +angle PQR = 180
65+65+angle PQR=180
130+angle PQR =180
angle PQR =180-130=50
QPR=65 , QRP=65 , PQR=50
C) step 1:- angle CAM + angle MAN=180
angle 135 + angle MAN =180
angle MAN =180-135=45
Step 2:-angle MAN = angle MNA [Same side]
Step 3:- angle MAN + angle MNA + angle AMN = 180
35+35+angle AMN =180
angle AMN =180-70=110
MAN = 35 , AMN = 110 , MNA = 35
mahisingh66:
thnku.. so much...
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