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Hey friend, Here is your answer-
Question no. 1 answer-
Let the areas of two similar triangles be A1 and A2.
Let their respective corresponding sides be S1 and S2.
A1 = 225 sq.cm
A2 = 81 sq.cm and S2 = 12 cm
By theorem of areas of similar triangles,
A1 / A2 = S1^2 / S2^2
225 / 81 = S1^2 / 12^2
S1^2 = 225 × 144 / 81
S1 = 15 × 12 / 9
S1 = 20 cm.
The corresponding side of the bigger triangle is 20 cm.
Hope it will help you.
Question no. 1 answer-
Let the areas of two similar triangles be A1 and A2.
Let their respective corresponding sides be S1 and S2.
A1 = 225 sq.cm
A2 = 81 sq.cm and S2 = 12 cm
By theorem of areas of similar triangles,
A1 / A2 = S1^2 / S2^2
225 / 81 = S1^2 / 12^2
S1^2 = 225 × 144 / 81
S1 = 15 × 12 / 9
S1 = 20 cm.
The corresponding side of the bigger triangle is 20 cm.
Hope it will help you.
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