Please solve these questions and best answer will be marked as a brainlist.
1 - A shopkeeper bought two fans for rupees 3120. He sold one of them at the profit of 36% and the other at a loss of 15%. He found that each fan was sold for the same price. Find the cost price of each fan.
2 - Sonika sells two jewellery boxes for rupees 1400 each. On one she earns a profit of 10% and on the other suffers a loss of 10%. Find her overall profit or loss percent.
Answers
Answered by
1
Let the CP of first fan be Rs a
CP of second fan = Rs (3120 - a)
Profit on first fan = 36%
SP of first fan = a + 36% of a
= a + 36a / 100
= 136a/100
Loss on second fan = 5%
SP of second fan = (3120 -a) - 5% of (3120-a)
= (3120 -a) - [5(3120 - a) / 100]
According to question
SP of first fan = SP of second fan
136a / 100 = {(312000-100a) - (15600 - 5a)} / 100
=> 136a = 312000 - 100a - 15600 - 5a
=> 241a = 296400
=> a = 1300 approx
CP of first fan = Rs 1300
Cp of second fan = Rs 1820
shivu2000:
Hey bro your anger is incorrect it is 1200 and 1920 not 1300 and 1820
Answered by
0
1. If C.P. of one fan is x then C.P. of another is 3120 - x
Then,
1.36 x = (3120 - x)0.85
1.36 x = 2652 - 0.85x
2.21x = 2652
x = 1200
So, C.P. of another fan = 3120 - 1200 = 1920
2. In such that cases...object having always loss And the trick is: {Common profit or loss/10}^2% So the answer will be Loss = {10/10}^2=1%
Then,
1.36 x = (3120 - x)0.85
1.36 x = 2652 - 0.85x
2.21x = 2652
x = 1200
So, C.P. of another fan = 3120 - 1200 = 1920
2. In such that cases...object having always loss And the trick is: {Common profit or loss/10}^2% So the answer will be Loss = {10/10}^2=1%
Similar questions
Computer Science,
7 months ago
English,
7 months ago
Math,
7 months ago
Math,
1 year ago
Math,
1 year ago