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Answer 1

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Answer 2

SOLUTION:-from the formula of limit we know that

$\frac{sinnx}{nx } = 1$

so,here we will just try to use that formula

$\frac{sin3x}{x } = 3 \times \frac{sin3x}{3x} \\ we \: know \: that \: limit \: of \: \frac{sinnx}{nx } = 1 \: if \: x \: trends \: to \: 0 \\ so \: \\ lim \frac{sin3x}{x} = 3 \times 1 = 1$