Please solve these questions:-
How to splitt that type == 3√3x(in question no.1)
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1) x²+3√3x +6 = x²+2√3x +√3x +6
x(x+2√3)+√3(x+2√3)
(x+2√3)(x+√3)
2) making denominator equal,
(8x²+2x-1)/8
1/8(8x²+2x-1). [taking 1/8 common]
1/8 ( 8x²+4x-2x-1)
1/8 ( 4x(2x+1)-1(2x+1) )
1/8 [(2x+1)(4x-1)]
is the answer
hope this helps you.......
x(x+2√3)+√3(x+2√3)
(x+2√3)(x+√3)
2) making denominator equal,
(8x²+2x-1)/8
1/8(8x²+2x-1). [taking 1/8 common]
1/8 ( 8x²+4x-2x-1)
1/8 ( 4x(2x+1)-1(2x+1) )
1/8 [(2x+1)(4x-1)]
is the answer
hope this helps you.......
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