Question

please solve these qusetions​

Answer 1

Step-by-step explanation:

$2.)( {5}^{ - 1} \times {2}^{ - 1} ) \times {6}^{ - 1} \\ = > ( \frac{1}{5} \times \frac{1}{2} ) \times \frac{1}{6} \: \: (because ({a})^{ - 1} = \frac{1}{a} ) \\ = > \frac{1}{10} \times \frac{1}{6} \\ = > \frac{1}{60}$

$3. ){5}^{m} \div {5}^{ - 3} = {5}^{5} \\ = > {5}^{m - ( - 3)} = {5}^{5} \\ = > {5}^{ m+ 3} = {5}^{5} \\ = > m + 3 = 5 \: (for \: cancellation \: law) \\ = > m = 5 - 3 \\ = > m = 2$

$1.) \frac{ {8 }^{- 1} \times {5}^{3} }{ {2}^{ - 4} } \\ = > \frac{ {2}^{4} \times {5}^{3} }{8} \\ = > \frac{ {2}^{4} \times {5}^{3} }{ {2}^{3} } \\ = > {2}^{4 - 3} \times {5}^{3} \\ = > {2}^{1} \times {5}^{3} \\ = > 2 \times {5}^{3} \\ = > {10}^{3} \\( because \: {a}^{m} \times {b}^{n} = {ab}^{mn} )$

6.)a.){(1/1/3-1/1/4)}^-1

==>. {3-4}^-1

=>-1^-1=-1

b.)(8/5)^2×(8/5)^-4

=>. (8/5)^2-4

=>. (8/5)^-2

=>. (5/8)^2

=>. 25/64