Question

Please solve these sums............please.....please

Answer 1

a-b =10 then (a-b)(a-b)=(10)(10)=100
a^2+2ab+b^2=49 then (a+b)=7
a+b=5. and a-b =3 and a^2-b^2=(a+b)(a-b)=(5)(3)=15

Answer 2

Hey !!! ^_^

Here is your answer

⬇️⬇️⬇️⬇️⬇️⬇️⬇️

1) ......

If ,. (a - b) = 10 ...

As we know ...


(a - b)²

= a² - 2ab + b²

So ,

(a - b)²

(10)2

100 ..

_______________________

2)

if .........

a² + 2ab + b ² = 49 ..

(a + b)² = 49

a + b = 7

______________________

(a + b) = 5 and (a - b) =3

As we know


a² - b²

(a + b)(a - b)

(5)(3)

15

so ,

a² - b² = 15 ...

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I HOPE IT WILL HELP YOU

Thank you

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