Question

Please solve these two question of linear equations in one variable and explain it with statement and steps.

1) Five years ago a man was seven times as old as his son. Five year hence, the father will be three times as old as his son. Find their present ages

2) I am currently 5 times as old as my son. In 6 years time I will be three times old as he will be then. What are our ages know? ​

Answer 1

Answer:

Step-by-step explanation:

1 - Age of the son =x

Age of the father=7x

Present ages=x+5 and 7x+5

future age of the son=x+10

father=7x+10

7x+10=3(x+10)

x=5

7x=35

x+5=5+5=10

son age =10

father age =7x+5=7*5+5=40

2- Let your son present age be x and yours 5x

As per question:

5x+6=3(x+6)

5x+6= 3x+18

5x-3x=18-6

2x=12, x= 12/2=6

So son age is 6years

then your age = 6×5= 30 years

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Answer 2

Answer:

Step-by-step explanation:

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