Question

Please solve theses questions​

Answer 1

0

Step-by-step explanation:

$2 \sqrt[3]{24} + 4 \sqrt[3]{81} - 4 \sqrt[3]{192}$

$2 \sqrt[3]{2 \times 2 \times 2 \times 3} + 4 \sqrt[3]{3 \times 3 \times 3 \times 3} - 4 \sqrt[3]{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3}$

$2 \times 2\sqrt[3]{3} + 4 \times 3 \sqrt[3]{3} - 4 \times 2 \times 2 \sqrt[3]{3}$

$4 \sqrt[3]{3} + 12 \sqrt[3]{3} - 16 \sqrt[3]{3}$

$16 \sqrt[3]{3} - 16 \sqrt[3]{3}$

= 0

Answer 2

Answer:

2 ³√24 = 4 ³√3

4 ³√81 = 12 ³√3

4 ³√192 = 16 ³√3

(2 ³√24) + (4 ³√81) + (4 ³√192) = (4 ³√3) + (12 ³√3) + (16 ³√3)

= ³√3 (4 + 12 - 16) = ³√3 (0) = 0