Question

please solve this........!!!!​

Answer 1

Answer:

answer is above in the picture. please check

Answer 2

Answer:

$\frac{3 + \sqrt{7} }{3 - 4 \sqrt{7} } = a + b \sqrt{7} \\ \frac{3 + \sqrt{7} }{3 - 4 \sqrt{7} } \times \frac{3 + 4 \sqrt{7} }{3 + 4 \sqrt{7} } \\ = \frac{9 + 12 \sqrt{7} + 3 \sqrt{7} + 4 \times 7 }{9 - 112} \\ = \frac{37 + 15 \sqrt{7} }{ - 103} \\ \frac{ - 37 - 15 \sqrt{7} }{103} = a + b \sqrt{7} \\ hence \: a = \frac{ - 37}{103} \\ b \sqrt{7} = \frac{ - 15 \sqrt{7} }{103} \\ b = \frac{ - 15}{103}$