Question

Please solve this!!!!!! ​

Answer 1

SOLUTION

For getting the sum of 4digits numbers we can apply the formula as follows:

=)(sum of given digit)× 1111....n (given number of digits)× (number of digit-1)!

=) Here, 3,4,5,6

=) (3+4+5+6) × (1111)× (4-1)!

=) (18) × (1111)× (3!)

=) 18× 1111× 3

=) 59994

hope it helps ☺️

Answer 2

Answer:

❤️ METHOD (1) ❤️

Four digit numbers = 4⋅3⋅2⋅1 = 24 ways

we can form a four digit number.

Since it's a 4 digit number, each digit will appear 6(24/4) times in each of units, tens, hundreds, and thousands place.

Therefore, the sum of digits in the units place is :-----

6(3+4+5+6) = 108

Similarly sum of digits at tens,hundreds,thousands place is 108 ..

Required sum of all numbers =

108+108*10+108*100+108*1000 = 119988 (Ans)

❤️ METHOD (2) ❤️

sum = (sum of given digits)×1 1 1 1_____n (given number of digits)*(number of digits−1)!

sum = (3+4+5+6)*1111*(4-1)!

sum = 18*1111*6

sum = 119988 (Ans)

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