Math, asked by AashayGupta, 1 year ago

please solve this???????????¿???​

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Answered by saishriyans
0

Answer:

oh lol cbse text book problem

Step-by-step explanation:

AD⇒AB

AC ⇒AE

∠BAE⇒∠EAC

∠A IS COMMON

BY SAS BOTH TRIANGLES ARE ≅

BY CPCT BC⇒DE

Answered by kumbha
0

Step-by-step explanation:

In triangle ABC and triangle ADE

<BAD=<EAC (given )

by adding <ADC to both sides we get :-

<BAC =<EAD

AB=AD (given )

AC=AE (given )

so, by SAS criteria ABC is congurent to ADE

So, by CPCT. BC=DE

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