please solve this???????????¿???
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Answer:
oh lol cbse text book problem
Step-by-step explanation:
AD⇒AB
AC ⇒AE
∠BAE⇒∠EAC
∠A IS COMMON
BY SAS BOTH TRIANGLES ARE ≅
BY CPCT BC⇒DE
Answered by
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Step-by-step explanation:
In triangle ABC and triangle ADE
<BAD=<EAC (given )
by adding <ADC to both sides we get :-
<BAC =<EAD
AB=AD (given )
AC=AE (given )
so, by SAS criteria ABC is congurent to ADE
So, by CPCT. BC=DE
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