Question

Please solve this?????​

Answer 1

Answer:

Area of the field =

(80 \times 50)m {}^{2} = 4000m {}^{2}(80×50)m2=4000m2

Area of the pit =

(10 \times 7.5)m {}^{2} = 75m {}^{2}(10×7.5)m2=75m2

Area over which the earth is spread out=

(4000 - 75)m {}^{2} = 3925m {}^{2}(4000−75)m2=3925m2

Volume of the earth dug out =

(10 \times 7.5 \times 8)m {}^{3} = 600m {}^{3}(10×7.5×8)m3=600m3

Rise in level= volume of the earth dugout

Area over which the earth spreadout

= ( \frac{600}{3925}) m = ( \frac{600 \times 100}{3925})cm = 15.3cm=(3925600)m=(3925600×100)cm=15.3cm

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Answer 2

Hey mate,

Answer:

6 . 57 metre

Step-by-step explanation:

In the given picture.

Hope it helps...

$( Itz ❤Aakanksha❤ here! ) {}^{}$