Question

please solve this............................​

Answer 1

Answer:

please check your answers

Answer 2

Step-by-step explanation:

In ΔABX and ΔCPX

∠ABX = ∠CPX ( alternate angle of parallel line, CD||AB)

∠BAX = ∠PCX ( alternate angle of parallel line, CD||AB)

Therefore, ΔABX ≈ ΔCPX (By AA similarity property)

If two triangles are similar then their corresponding sides are in proportion.

Therefore,

But AB = 2PC -------1 (AB=CD opposite side of parallelogram and P is mid point of CD)

CX = AC - AX-------2

Put the value in equation

$\frac{ AB}{PC} = \frac{AX}{CX} \\ \\ \frac{2PC}{PC} = \frac{AX}{ AC - AX} \\ \\ 2 AC - 2AX = AX \\ \\ 2AC = AX + 2AX \\ \\ 2AC = 3AX \:$