please solve this.....
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Answer:
a^p = b^q = c^r = abc
So,
a^p * b^q * c^r = (abc)*(abc)*(abc)
= a^3 b^3 c^3
On comparing the exponents of each of the bases on both sides, it's uniquely Det that p=q=r = 3
or,
pqr = 27
What remains is to find out which expression in the given option also equals to 27 on putting p=q=r = 3
So,
option (B)
pq + qr + pr = (3)(3)+(3)(3)+(3)(3) = 3*9 = 27
Hence the correct answer will be option (B).
hope this helps you!
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