Math, asked by shekharkumaryadav877, 8 months ago

please solve this.....​

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Answers

Answered by PhysicsForever
1

Answer:

There's a misprint in the question I suppose, it should be 140-19 instead of 140-29

If that's true then it follows that

=> ((23+2^2)^2/3 + (140-19)^1/2)^2

= ((23+4)^2/3 + (121)^1/2)^2

= ((27)^2/3 + 11)^2

= ((3^2 + 11)^2 = (20)^2 = 400

Hope this helps you !

Answered by khalkaraditya8
1

Answer:

answer should be (d)400

but the thing is that it should be 150 or -19 in the question in second bracket.

Step-by-step explanation:

see,[(23+4)2/3+(140-29)1/2]2

so,[(27)2/3+√111]2

so,[9+√111]2

so, if it was 121 we get

[9+11]2

=20^2

=400

PLEASE MARK MY ANSWER AS BRAINLIEST BECAUSE YOU WILL GET POINTS FOR THAT

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