Question

please solve this ........

Answer 1

➞ x - 1 = 0

➞ x = 0 + 1

.°. x = 1

______________________....

Now we put the value of x = 1

➞2x³ - 4x² + 6x - k

➞2(1)³ - 4(1)² + 6 × 1 - k = 0

➞2 - 4 + 6 - k = 0

➞4 - k = 0

➞- k = 0 - 4

➞- k = - 4 [ Both side minus is cancelled]

.°. k = 4.

______________________....

• Option (1) is correct

Answer 2

Answer:

Step-by-step explanation:

I have attached the answer