Math, asked by deodeoprakash, 9 months ago

please solve this. ​

Attachments:

Answers

Answered by tanisksaxena2020
1

Answer:

(tan(90-theta)cot theta) /cosec.^2theta -cos^2 theta =0

by using L. H. S.

(tan90- theta) cot theta) /cosec^2 theta -cos^2 theta

=cot theta (cot theta) /cosec^2 theta -cos^2 theta

= cot ^2 theta /cosec^2 theta -cos^2 theta

=(cosec^2 theta /sec^2 theta) /cosec^2 theta) -cos^2 theta

=1/sec^2 theta - cos^2 theta

=cos^2 theta-cos^2theta

=0

hence, L. H. S. =R. H. S.

I HOPE IT WILL HELP YOU

Similar questions