Please..... solve this
Answers
QUESTION
In a Youngs double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in the experiment.
ANSWER
Distance between the slits, d=0.28×10−3 m
Distance between the slits, d=0.28×10−3 mDistance between the slits and the screen, D=1.4m
Distance between the slits, d=0.28×10−3 mDistance between the slits and the screen, D=1.4mDistance between the central fringe and the fourth (n=4) fringe,
Distance between the slits, d=0.28×10−3 mDistance between the slits and the screen, D=1.4mDistance between the central fringe and the fourth (n=4) fringe, u=1.2×10−2 m
Distance between the slits, d=0.28×10−3 mDistance between the slits and the screen, D=1.4mDistance between the central fringe and the fourth (n=4) fringe, u=1.2×10−2 mIn case of a constructive interference, we have the relation for the distance between the two fringes as:
Distance between the slits, d=0.28×10−3 mDistance between the slits and the screen, D=1.4mDistance between the central fringe and the fourth (n=4) fringe, u=1.2×10−2 mIn case of a constructive interference, we have the relation for the distance between the two fringes as:u=nλD/d
Distance between the slits, d=0.28×10−3 mDistance between the slits and the screen, D=1.4mDistance between the central fringe and the fourth (n=4) fringe, u=1.2×10−2 mIn case of a constructive interference, we have the relation for the distance between the two fringes as:u=nλD/d⇒λ=ud/nD=6×10−7m=600nm
Answer:
Welcome back Goldi . Finally your exams are over...I really missed you so much...
Thanx for giving me endless thanks ❤️
No need to give more thanks as fingers will pain
Love you Goldi☺
Explanation:
I PURPLE YOU ❤️❤️❤️