Question

please solve this ................................ ​

Answer 1

Answer:

(2a²- b²)/ b²

Step-by-step explanation:

just try to rationalize

Answer 2

Answer:

Step-by-step explanation:

let root of 'a'square minus 'b' square be= 'x'

therefore- (a+x)/(a-x) + (a-x)/(a+x)

taking LCM as (a-x)*(a+x)

(a+x)^2 + (a-x)^2/a^2-x^2

a^2+x^2+2ax + a^2+x^2-2ax/ a^2-x^2

a^2+x^2+a^2+x^2/a^2-x^2

2a^2+2x^2/a^2-x^2

now substitute the original values in place of x and then simplify