Question

please solve this......​

Answer 1

❣ᴏᴋ ᴅɪ ɴɪᴄᴇ ᴅᴀʏ❣

❥ʜᴇʀᴇ ɪs ʏᴏᴜʀ ʀɪɢʜᴛ ᴀɴsᴡᴇʀ

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Answer 2

Answer:

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Solution

In Δ ABC, right-angled at B

using Pythagoras theorem

we have

AC² = AB² +BC²

AC² = 24² + 7²

AC²576 + 49

AC²= 625

AC = √625

AC = 25

Now

In a right angle triangle ABC where B=90°

(i) Sin A = BC/AC = 7/25

CosA = AB/AC = 24/25

(ii) Sin C = AB/AC = 24/25

Cos C = BC/AC =7/25

Sin. C cos C

(ii) sinC=

AC

AB

=

25

24

;cosC=

AC

BC

7/ 25