Question

please solve this ​

Answer 1

3^(4x + 1) = (1/9)^(x + 1)

3^(4x + 1) = (1/3^2)^(x + 1)

3^(4x + 1) = (3^(-2))^(x + 1)

3^(4x + 1) = 3^(-2x - 2)

equating the exponent as base is. same

4x + 1 = -2x - 2

4x + 2x = -2 - 1

6x = -3

x = -3/6

x = -1/2