Math, asked by gangurdesnehal96, 7 months ago

PLEASE SOLVE THIS .​

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Answered by dhruvsh
5

Answer:

LHS

= sec A + tan A

= 1/cos A + sin A/cos A

= (1+sinA)/cosA

= (1+sinA)(1-sinA)/cosA(1-sinA)

=1-sin^2A/cosA(1-sinA)

= cos^2 A/cos A(1-sinA)

= cos A /1-sinA

= RHS

Hence, proved. 。◕‿◕。

Answered by mrmajnu51
1

Step-by-step explanation:

Answer ✍️

____________

  • LHS
  1. = sec A + tan A
  2. = 1/cos A + sin A/cos A
  3. = (1+sinA)/cosA
  4. = (1+sinA)(1-sinA)/cosA(1-sinA)
  5. =1-sin^2A/cosA(1-sinA)
  6. = cos^2 A/cos A(1-sinA)
  7. = cos A /1-sinA
  • = RHS

hope this helps you

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