Question

Please solve this..​

Answer 1

Step-by-step explanation:

i am not able to understand this question so if one no the answer tell me

Answer 2

Answer:

$\int\limits {\frac{e^{5logx}-e^{4logx}}{e^{3logx}-e^{2logx}}} \, dx$ = x³/3

Step-by-step explanation:

Given: $\int\limits {\frac{e^{5logx}-e^{4logx}}{e^{3logx}-e^{2logx}}} \, dx$

or $\int\limits {\frac{e^{logx^{5}}-e^{logx^{4}}}{e^{logx^{3}}-e^{logx^{2}}}} \, dx$              {∵n log m = log mⁿ}

or $\int\limits {\frac{x^{5}-x^{4}}{x^{3}-x^{2}}} \, dx$                       {∵$e^{logx}$ = x}

or $\int\limits {\frac{x^{4}(x-1)}{x^{2}(x-1)}} \, dx$

or $\int\limits {x^{2}} \, dx$

⇒ x³/3

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