please solve this 3,9,10 questions urgently
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k2w2:
to draw and then get the answer
a b c
that will be the names ok
make it fast
wht
ill try my best
make it brillant'
if u like
brilliant
sorry
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ans 9= the sum of two sides of a triangle is greater than twice the median bisecting the third side, hence in ABD , AD is a median ab+ac >2{AD} SIMARLY we get bc+ac>2cf
bc+ab>2be on adding the above equations we get
[ac+ab]+[bc+ac]+[bc+ab]>2ad+2cd+2be
2[ab+bc+ac]>2[ad+be+cf]
ab +bc +ac >ad +be +cf
now we can say the perimeter of the triangle is greater than the medien.
ans 10=to prove the hypotenuse iof a right angled triangle is the longest side ,we use the PYTHAGORAS THE OREM i.e_ a*a=b*b+c*c
where a= hypotenuse
b and c = the sides of the triangle
bc+ab>2be on adding the above equations we get
[ac+ab]+[bc+ac]+[bc+ab]>2ad+2cd+2be
2[ab+bc+ac]>2[ad+be+cf]
ab +bc +ac >ad +be +cf
now we can say the perimeter of the triangle is greater than the medien.
ans 10=to prove the hypotenuse iof a right angled triangle is the longest side ,we use the PYTHAGORAS THE OREM i.e_ a*a=b*b+c*c
where a= hypotenuse
b and c = the sides of the triangle
thanks a lot
u were very helpful to me
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